Решение задачи «Слить N каналов в один»
package main
import (
"fmt"
"sync"
)
func joinChannels(chs ...<-chan int) <-chan int {
mergedCh := make(chan int)
go func() {
wg := &sync.WaitGroup{}
wg.Add(len(chs))
for _, ch := range chs {
go func(ch <-chan int, wg *sync.WaitGroup) {
defer wg.Done()
for id := range ch {
mergedCh <- id
}
}(ch, wg)
}
wg.Wait()
close(mergedCh)
}()
return mergedCh
}
func main() {
a := make(chan int)
b := make(chan int)
c := make(chan int)
go func() {
for _, num := range []int{1, 2, 3} {
a <- num
}
close(a)
}()
go func() {
for _, num := range []int{20, 10, 30} {
b <- num
}
close(b)
}()
go func() {
for _, num := range []int{300, 200, 100} {
c <- num
}
close(c)
}()
for num := range joinChannels(a, b, c) {
fmt.Println(num)
}
}